please make it in stander quadratic form
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Hey there,
x²-2(a+2)x+(a+1)(a+3)=0
x²-2ax-4x+a²+4a+3=0 {By opening brackets}
x²+x(-2a-4)+(a²+4a+3)=0
Since its in the form px²+qx+r
where p=1, q=-2a-4, r=a²+4a+3
So it is in standard form...
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
x²-2(a+2)x+(a+1)(a+3)=0
x²-2ax-4x+a²+4a+3=0 {By opening brackets}
x²+x(-2a-4)+(a²+4a+3)=0
Since its in the form px²+qx+r
where p=1, q=-2a-4, r=a²+4a+3
So it is in standard form...
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
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