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Slant height of each cone (l)=(1)2+(0.2)2−−−−−−−−−−√ m
=1.04−−−−√m=1.02m
∴ Area to be painted for 50 hollow cones
=50×πrl
=(50×3.14×0.2×1.02)m2
=32.028 m2
Cost of painting =₹ 12×32.028
=₹ 384.34 approx..
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best of luck for your exams
i am sure u will get 10000 marks out of 100 :)
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