Question

Please may someone help me....

Suggest a reason for only ‘roughly’ twice as much hydrogen gas being produced at the cathode as oxygen gas at the anode in the electrolysis of water.​

Answer 1

Answer:

Here is your answer

Explanation:

The chemical equation is

2H2O gives 2H2+O2

The simple answer is that because the stoichometric coefficient/mole of hydrogen is twice than that of oxygen. The amount of hydrogen formed will be twice than that of hydrogen hence hydrogen formed is twice of oxygen.

If we consider the dissociation, then

2H2O-->2H2+O2

Let moles of H2O be x. Then product formed will be

x-2y 2y y

0 2y y

From this you can say that the amt. of hydrogen is twice than that of oxygen.

Of you don't know what mole is, here consider it to be the coefficient of elements in the reaction.

Does it help?