Question

please mention the above answer​

Answer 1

Answer:

${x}^{2} - 3 \sqrt{3x} + 6 = 0 \\ d = {b}^{2} - 4ac \\ ( - 3 \sqrt{3) {}^{2} } - 4(1)(6) = 0 \\ 27 - 24 = 0 \\ 3 = d \\ x = \frac{ - b + \sqrt{d} }{2a} \\ x = \frac{ - ( - 3 \sqrt{3)} + \sqrt{3} }{2} \\x = \frac{3 \sqrt{3} + \sqrt{3} }{2} \\ x = \frac{ \sqrt{3}(3 + 1) }{2} \\ x = \frac{ \sqrt{3}(4) }{2} \\ x = 2 \sqrt{3} = answer$

I hope this is your answer

Answer 2

Answer:

Option 2√3 is the answer.