Math, asked by shrutithakur14, 4 months ago

please mention the steps also ​

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Answered by gaadha55
0

OAB = 60°

ACB = 90°

Given

angle AOB = 90°

and

angle ABC = 30°

In triangle AOB

angle AOB = 90°

angle ABO = 30°

° angle OAB = 180° - (90°+30°)

= 180° - 120°

= 60° ----------1

In triangle ACB

angle CAB = 60° ( from 1 )

angle CBA = 30°

angle ACB = 180° - ( 60°+30°)

= 180° - ( 90°)

= 90°

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