Question

please mere pyare bhaiyo and ldkiyon ,isks answer do ,how to count sigma and pi bond in N2,N2(+),O2 and O2(+)​

Answer 1

to count the number of sigma and pi bonds if you have already drawn the structure of the compound.

All single bonds will always be a sigma bond

In a double bond one of the bond is always a sigma and other one a pi bond.

In a triple bond one of the bond is sigma and the other two are pi bonds.

Answer 2

Hey mate!!
_______________★_★



★ To find Number of sigma bond

FORMULA = (VALENCE ELECTRON + - charge) ÷ 8

★ TO find number of lone pair

Formula = Remainder ÷ 2

1) N2

→ Valence electron = 5+5 = 10

★ number of sigma bond = 10/8 = 1

【 remainder =2】

● lone pair = 2/2 = 1

● number of pi bond =

since, vale e- of each N is 5

1 e- participate in sigma bond
2 e- in lone pair

◆ Remaning 2 e- in pi bond.

so, number of pi bond = 2

similarly, you can find number of pi, sigma and lone pair in O2

→ for, N2+ and O2+ ....
and H containing compound you hav to draw structure.

hope it helps!!

#Jaihind