Question

please mere question ka jaldi se answer dijiye aur bilkul formula mein​

Answer 1

✴ Hey friends!!✴✴

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✴✴ Here is your answer↓⬇⏬⤵

⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇

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▶⏩ Let the given angle = angle A= 80°.

=> We know that:-)

↪➡ The sum of adjacent angles of parallelogram is 180°.

↪➡ angle A + angle B = 180°.

↪➡ 80° + angle B = 180°.

↪➡ angle B = 180° - 80°.

↪➡ angle B = 100°.

=> We know that:-)

↪➡ Opposite angles of parallelogram are equal.

↪➡ angle A = angle C.

↪➡ angle C = 80°.

▶⏩ Now,

↪➡ angle B = angle D.

↪➡ angle D = 100°.

✔✔ Hence, all angles are :-)

=> angle A = 80°.✅✅

=> angle B = 100°.✅✅

=> angle C = 80°.✅✅

=> angle D = 100°.✅✅

⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴

✴✴ Thanks!!✴✴.

☺☺☺ Hope it is helpful for you ✌✌✌.

Answer 2

How to do:-

here, it is given that the angle 2 in the transversal measures 80° and that we have to find the other angles in the transversal so, let's apply suitable properties of lines and angles so that we will find the rest angles

Given :-

• The Angle 2 in the transversal measures 80 degrees

To Find :-

• The rest of the angles in the transversal

Solution :-

As we know that,

${ \large{\gray{ \boxed{ \gray{ \tt{ \bigstar \: vertically \: opposite \: angle \: are \: equal}}}}}}$

Here,

• Angle 2 and angle 4 are vertically opposite angles

$\leadsto \tt \angle \: 2 = { \boxed{\tt \angle4}} \\ \\ \\ \leadsto \tt 80 \degree = \pink{ \boxed{\tt \angle4}}$

Hence,

• Angle 3 measures 80°

We know that,

${ \large{\gray{ \boxed{ \gray{ \tt{ \bigstar \: linear \: pair \:measures \: 18 0 \degree }}}}}}$

Here,

• Angle 1 and angle 2 form a linear

$\leadsto \tt \angle \: 1 + (2) = 18 0 \\ \\ \\ \leadsto \tt \angle \: 1 + 80 \degree = 180 \\ \\ \\ \leadsto \tt \angle \: 1 = 180 - 80 \: \\ \\ \\ \leadsto \tt \angle \: 1= \blue{ \boxed{ \tt{100 \degree}}} \: \: \: \: \: \:$

Hence,

• Angle 1 measures 100°

So, as angle 1 and angle 3 are vertically opposite angles

• Angle 3 measures 100°

Therefore,

• The angles are 100°, 100° and 80°