Question

please my dear friends, answer the following: A thin glass rod is bent into a semicircle of radius R. A charge + Q is uniformly distributed along the upper half, and a charge -Q is uniformly distributed along the lower half, as shown in the figure. If Q = 10 nC and the electric field E at point P is 5.85 ´ 104 N/C in -y direction, what is the radius of the semicircle, R? Point P is at the center of the semicircle.

Answer 1

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Answer 2

hope it helps you with best wishes