please need fast only no2 please help me out of this problem
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8. (ii)
Given x = 2√3 + 2√2
Then, 1/x = 1/(2√3 + 2√2)
We rationalise the denominator by multiplying the conjugate irrational number (2√3 - 2√2) to both the numerator and the denominator.
= (2√3 - 2√2)/{(2√3 + 2√2)(2√3 - 2√2)}
= (2√3 - 2√2)/(12 - 8)
= (2√3 - 2√2)/4
So, x + 1/x
= (2√3 + 2√2) + (2√3 - 2√2)/4
= (8√3 + 8√2 + 2√3 - 2√2)/4
= (10√3 + 6√2)/4
= (5√3 + 3√2)/2
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