Question

please needed answer​

Answer 1

Answer:

${16}^{2x - 1} = {8}^{x + 2} \\ { {2}^{4} }^{(2x - 1)} = { {2}^{3} }^{(x + 2)} \\ {2}^{4(2x - 1)} = {2}^{3(x + 2)} \\ {2}^{8x - 4} = {2}^{3x + 2} \\ as \: base \: is \: equal \: we \: can \: equat \: power \\ 8x - 4 = 3x + 2 \\ 8x - 3x = 4 + 2 \\ 5x = 6 \\ x = \frac{6}{5}$

Answer 2

Step-by-step explanation:

First write in exponential form

then multiply the numbers

then set equal exponents

move constant to the right

calculate and divide both sides by 8