Question

please no 6 in the attachment ​

Answer 1

Answer:

angle in a semicircle is 90°

∠ACB=90

3)∠BDA=90

∠CBD=90

∠CAD=90

1) ∠ACB=90

  ∠ACD+∠BCD=90

  ∠ACD=90-43

  ∠ACD=47°

2)IN ΔBDA

∠BAD+∠ABD+∠BDA=180  (ANGLE SUM PROPERTY)

∠BAD+54°+90°=180°

∠BAD=180-144

∠BAD=36°

Step-by-step explanation: