please no spamming pls answer q.no.2 if u know pls pls
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Hello,
i know the answer to (b) part of the question here it is :-
[(2/3)^7] * (2/3)^ -35
ANSWER :- LAWS USED
(2/3)^7*5 x (2/3)^ -35 (a)^m*n = (a)^mn
(2/3)^35 x (3/2)^35 (a)^ -m = (1/a^m)
[(2/3 x (3/2)]^35 (a)^m * (b)^m = (ab)^m
(1)^35 (1)^a = 1
= 1
While solving such questions always remember to write the laws because they carry marks in exams.
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