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x^x^1/x = (x *x^1/x)^x
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The final answer is one though I had not done it regrousily but still we can guess the answer
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in this question x and √x get in multiply then second x go in braket square
Step-by-step explanation:
like that. then (x√x) be P
x raise to x√x =(x√x) raise to x
= x × x√x
= (x√x) raise to x
= (P) raise to x
hope it is useful to u
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