please only correct answer physics 25 points
The kinetic energy K of a particle moving along a circle of radius R depends upon the distance s as K=as^2 .find the force acting on particle.
Answers
Answered by
3
Given 1/2mv²=as²Differentiating both sides w.r.t. time
We get. Tangential accn(w1) =2as/m
Centripetal acceleration(w2)
Now net accn=√[(w1)² + (w2)²]
=√[(2as/m)² + (2as²/mR)²]
=2as/m √[1+(s/R)²]
Now total force=m× net acceleration 2as√[(1+s²/R²)]
We get. Tangential accn(w1) =2as/m
Centripetal acceleration(w2)
Now net accn=√[(w1)² + (w2)²]
=√[(2as/m)² + (2as²/mR)²]
=2as/m √[1+(s/R)²]
Now total force=m× net acceleration 2as√[(1+s²/R²)]
Answered by
2
see the solution in above image.
Attachments:
Similar questions