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Answers
Answer:
(d) 2x-3y=17;4x+y-13=0
2x-3y-17=0;4x+y-13=0
For y
y=-4x+13
Substitute y in
2x-3(-4x+13)=17
14x=56
x=4
Substitute x in
y=-4(4)+13
=-16+13=-3
y=-3
Therefore x,y=4,-3
(e)x+2y-7=0;2x-y-4=0
x=-2y+7
substitute x in
2(-2y+7)-y=4
-5y=-10
y=2
substitute y in
x=-2(2)+7
x=-4+7
x=3
Therefore x,y=3,2
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d)
▪︎ 2x-3y = 17 ---(1).
▪︎ 4x+y-13 = 0
=》 4x+y = 13. ---(2).
▪︎ By Multiplying eq(2) by 3 we get,
=》 3{4x+y = 13}
=》 12x+3y = 39. ---(3).
▪︎ By Adding eq(1) and eq(3) we get,
=》 (2x-3y)+(12x+3y) = 17+39.
=》 2x-3y+12x+3y = 56.
=》 2x+12x+3y-3y = 56.
=》 14x = 56.
=》 x = 56/14.
By putting the value of x in eq(1) we get,
=》 2(4) - 3y = 17.
=》 8 - 3y = 17.
=》 -3y = 17-8.
=》 -3y = 9
=》 y = 9/-3
Therefore the required value of x and y is 4 and -3 respectively.
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e)
▪︎x+2y-7 = 0.
=》 x+2y = 7. ---(1).
▪︎ 2x-y-4 = 0
=》 2x-y = 4. ---(2).
▪︎ By Multiplying eq(1) by 2 we get,
=》2{x+2y = 7}
=》 2x+4y = 14. ---(3).
▪︎ By subtracting eq(2) from eq(3) we get,
=》 (2x+4y) - (2x-y) = 14-4.
=》 2x+4y-2x+y = 10
{By Opening Brackets}
=》 5y = 10.
=》 y = 10/5.
▪︎ By putting the value of y in eq(1) we get,
=》 x+2(2) = 7.
=》 x+4 = 7.
=》 x = 7-4.
Therefore the required value of x and y is 3 and 2 respectively.
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