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Answers
Answer:
1. We measure the time period of 20 oscillations and divide it by 20. In other words, we derive the average time for oscillations.
We note the time for more than one oscillation since the least count of a stopwatch is not so small to measure such small time periods accurately,
Answer:
How to analyze a pendulum in swing
Determine the length of the pendulum. ...
Decide a value for the acceleration of gravity. ...
Calculate the period of oscillations according to the formula above: T = 2π√(L/g) = 2π * √(2/9.80665) = 2.837 s .
Find the frequency as the reciprocal of the period: f = 1/T = 0.352 Hz .
The period of a simple pendulum is T=2π√Lg T = 2 π L g , where L is the length of the string and g is the acceleration due to gravity.
How is time period measured?
Period refers to the time for something to happen and is measured in seconds/cycle. In this case, there are 11 seconds per 33 vibrational cycles. Thus the period is (11 s) / (33 cycles) = 0.33 seconds. We now know that the period is 3.2 seconds and that the frequency is 0.31 Hz.
Time period is the time taken by the body to complete one oscillation and it is noted more than once to get accurate reading from averaging of all the observed values.
To double the period of oscillation of a simple pendulum
A. The mass of its bob should be doubled.
The mass of its bob should be quadrupled.
Its length should be quadrupled.
Its length should be doubled.
Explanation:
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