Question

Please paper pe solve kar do . screen pe mat karna​

Answer 1

Answer:

1) In ∆ AEP and ∆ CDP,

|PEA = |PDC = 90° A

|APE = |CPD [ vertically opposite angles ] A

by AA similarity rule, ∆ AEP ~ ∆ CDP

2) In ∆ ABD and ∆ CBE,

|ADB = |CEB = 90° A

|ABD = |CBE [ common vertex hence common angle] A

by AA similarly rule, ∆ ABD ~ ∆ CBE