Question

please peepl the question is
If the circle is the maximum possible circle inscribed in the square on the given cartesian plane, what is the value of x?

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Answer 1

Answer:

x=9

Step-by-step explanation:

AB is equal to dia of circle

and AB=√(4+16)=√20=2√5

C is mid point of AB so coordinates of C are:

{ (4+6)/2,(5+9)/2}

or(5,7)

Now CD=dia=AB=√20

so √(5-x)²+(7-2)²=√20

(5-x)²+4=20

(5-x)²=16=4²

5-x=±4

x=5±4

thus x=5+4=9

or x=5-4=1

But x>4 so x=9