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Vector OA and vector OB are perpendicular and equal magnitude.
so, their resultant will be along angle bisector of angle AOB ..i.e. along OC.
and magnitude of their resultant = √2 R
so, |OA + OB| = √2 R ...... (i)
now,
|OC| = R ........ (ii)
since, Vectors (OA + OB) and OC are along line OC...
hence,
| OA + OB + OC | = √2 R + R = (√2 + 1)R ....ans...
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