Question

please please answer​

Answer 1

Please clarify the question

Answer 2

Answer:

(2)334/616 μF

(3)216/31 μF

Explanation:

• first diagram is not clear

• here is effective capacitance for second diagram :

• For upper arm series combination :

$\frac{1}{Ceq1} = \frac{1}{3} + \frac{1}{2}$

$Ceq1=\frac{6}{5}$

• For lower arm series combination :

$\frac{1}{Ceq2}= \frac{1}{5} +\frac{1}{4}$

$Ceq2= \frac{20}{9}$

• For upper arm and lower arm in parallel :

$Ceq3 = Ceq1+Ceq2$

$Ceq3 = \frac{154}{45}$

• Now for Ceq3 and side arm in series :

$\frac{1}{Ceq} =\frac{45}{154} +\frac{1}{4}$  μF

$Ceq=\frac{334}{616}$ μF

• for diagram three :

• For upper arc all are in series :

$\frac{1}{Ceq'}= \frac{1}{5}+ \frac{1}{3}+ \frac{1}{2}$

$Ceq'=\frac{30}{31}$

• Now the chord and arc are in parallel :

$Ceq= Ceq' + 6$

$Ceq= \frac{216}{31}$ μF