Question

please please answer its urgent ​

Answer 1

Answer:

Answer:–

• Height of the image,hi=3cm

Given:–

• Height of the object,ho=2cm
• Focal length of the mirror,f=12cm
• Object distance,u=20cm
• Radius of curvature,R=24cm

To find:–

• Height of the image,ho=?

Solution:–

From the mirror equation,

1/f=1/u+1/v

1/12=1/20+1/v

1/v=5-3/60

1/v=2/60

v=30cm

When the object placed between f and c then the image will get beyond c.

The image is real and inverted.

so,

Magnification,m=v/u=hi/ho

→ 30/20=hi/2

→ 3/2=hi/2

→ hi =3cm

So, Height of the image=3cm

Answer 2

Answer:

heigh of image =3

hope this help you