please please answer me correctly or I will report you
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Answer:
case 1)
a= v+u/t
= 8-0/40
=8/40
a1= 1/5
a1= 0.2ms^-2
case 2)
a=v+u/t
= 5-8/5
=-3/5
a2 =-0.6ms^-2
a2 is in negative as it is the declaration, as the brakes are applies.
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1st case:-
Given:-
•Initial velocity(u)=0
•Final velocity(v)=8m/s
•Time(t)=40s
To find:-
•Acceleration(a)
Solution:-
We know that----
=>a=v-u/t
=>a=8-0/40
=>a=8/40
=>a=1/5
=>a=0.2m/s²
2nd Case:-
Given:-
•Initial velocity(u)=8m/s
•Final velocity(v)=5m/s
•Time(t)=5s
To find:-
•Acceleration(a)
Solution:-
We know that-----
=>a=v-u/t
=>a=5-8/5
=>a= -3/5
=>a= -0.6m/s²
Thus acceleration is----
i.0.2m/s² in 1st case
ii. -0.6m/s² in 2nd case.
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