Question

please please answer me it is an question of 3 marks​

Answer 1

heya mate!!

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1. the max speed is10ms^-1 and is maintained for 380secs
2. acc =tan¤ =10/40=1/4 for OA and for AB =0 Then BC=tan¤=10/500=- 1/50
3. total distance is area under under vel- time graph so,,

for (1)=1/2*40*10=200

for(2)=380*10=3800

for(3)=1/2*10*80=400

total distance =200+400+3800

=4,400m

hope it helps u mate!!