Question

please please answer this question 7 a and 7 b

Answer 1

Answer:

Step-by-step explan

Ang ADE=DEC=55°[alternate interior ang]

Ang ADE+EDC=180°

55°+ t=180°[ang EDC=t]

t= 180°- 55°=125°

Ang EDC+DCE+DEC= 180°[sum of ∆]

125°+x+55°=180°

X=180°-180°=0°

Now,

Ang DEC+DEA=180°

55°+DEA=180°

DEA= 180°-55°=125°

Ang DAE+ADE+AED=180(sum of ∆)

f+55°+125°=180°

f=180°-180°=0°

Answer 2

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