please please answer this question
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4 vibrations = 1sec
1 vibration =1/4 sec
6 vibrations =6/4 sec
V = 340m/s
d=Vt/2
= 340*6/4*2
= 2040/8
=255m
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Time taken for 1 vibration =1/5s
Time taken for 8 vibration =8/5s
We know,
2d=vt
Therfore,
D=vt/2(where d=distance between the observer and the cliff)
V=velocity of sound
T=time taken for the sound to go and return
D=(340*8/5*2)m
D=272m
So the distance between the cliff and observer is 272
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