Question

please please answer this two sum​

Answer 1

Answer:

$11.) \: \: \: 3x + 2y = 11.....i \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2x - 3y = - 10.........ii \: \\ \\ multiplying \: eq \: i \: by \: 3 \\ \\ 3(3x + 2y) = 11 \times 3 \\ \\ 9x + 6y = 33.......iii \\ \\ multiplying \: eq \: ii \: by \: 2 \\ \\ 2(2x - 3) = - 10 \times 3 \\ \\ 6x - 6 y= - 30........iv \\ \\ adding \: \: \: \: \: eq \: \: \: \: \: \: \: iii \: \: \: \: \: \: \: and \: \: \: \: \: \: \: iv \\ \\ \: \: \: \: \: 9x + 6y = 33 \\ ( + )6x - 6y = - 30 \\ \\ 15x = 3 \\ \\ x = \frac{3}{15} = \frac{1}{5} \\ \\ substituting \: the \: value \: of \: x \: in \: eq \: \: \: \: \: i \\ \\ 3( \frac{1}{5} ) + 2y = 11 \\ \\ \frac{3}{5} + 2y = 11 \\ \\ 2y = 11 - \frac{3}{5} \\ \\ 2y= \frac{55 - 3}{5} \\ \\ 2y = \frac{52}{5} \\ \\ y = \frac{52}{5 \times 2} = \frac{26}{5} \\ \\ y = \frac{26}{5} \\ \\ \\ so \: \: \: \: x = \frac{1}{5} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: y = \frac{26}{5} \\ \\ \\ 12.) \: \: \: \: \: 2x - 3y = - 6......i \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2x + 3y = 18......ii \\ \\ adding \: \: \: \: eq \: \: i \: \: \: and \: \: \: ii \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2x - 3y = - 6 \\ ( + ) \: \: \: \: 2x + 3y = 18 \\ \\ 4x = 12 \\ \\ x = \frac{12}{4} = 3 \\ \\ x = 3 \\ \\ substituting \: the \: value \: of \: x \: in \: the \: eq \: \: \: \: i \\ \\ 2 \times 3 - 3y = - 6 \\ \\ 6- 3y = - 6 \\ \\ - 3y = - 6 - 6 \\ \\ y = \frac{ - 12}{ - 3} = 4 \\ \\ y = 4 \\ \\ \\ so \: \: \: \: x = 3 \\ \: \: \: \: \: \: \: \: \: \: y = 4 \\ \\ \\ hope \: it \: helps$