Math, asked by anjalina2828, 11 months ago

please please do step by step​

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Answered by niteshya916640
4

Answer:

According question

first square

perimeter of first square = 60 meters

We know that the perimeter of a square = 4×side of square

Let the side of square is a meter

Then 4a = 60

a = 60/4

a = 15 meters

The area of first square = side × side 15^2 = 225m^2

Now in second square:

perimeter of the second square = 144meters

Let the side of second square = b meter

Then 4a = 144

a = 144/4

a = 36 meters

The area of second square = side×side 36^2 = 1296m^2

According to question the area of the third square = area of first square + area of second square

= 1296 + 225

= 1521m^2

Let the side of third square = c meter

Then c×c = 1521

c = 39 meters

The perimeter of third square

4×C = 4 × 39

= 156 meters

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