Math, asked by biggboss945501, 1 month ago

please please doooooooo​

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Answered by BabyTaeny
11

Answer:

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Solve:3/2p²+2/3q²,(2p²-3q²)

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1.Combine multiplied terms into a single fraction.

  \sf{\frac{3 {p}^{2} }{2}  +  \frac{2}{3}. {q}^{2}(2 {p}^{2} - 3 {q}^{2} )   }

2.Combine multiplied terms into a single fraction.

 \sf{ \frac{3 {p}^{2} }{2}  +  \frac{2 {q}^{2}(2 {p}^{2}  - 3 {q}^{2} ) }{3} }

3.Distribute

 \sf{ \frac{3 {p}^{2} }{2} +  \frac{4 {p}^{2} {q}^{2} - 6 {q}^{2}   }{3}  }

4.Find common denominator

 \sf{ \frac{3.3 {p}^{2} }{6} +  \frac{2(4 {p}^{2}  {q}^{2}  - 6 {q}^{4}) }{6}  }

5.Combine fraction with common denominator.

  \sf{\frac{3.3 {p}^{2}  + 2(4 {p}^{2} {q}^{2}   - 6 {q}^{4} )}{6} }

6.Multiply the numbers.

 \sf{ \frac{9 {p}^{2}  + 2(4 {p}^{2} {q}^{2} - 6 {q}^{4}  ) }{6} }

7.Distribute.

 \sf{ \frac{9 {p}^{2}  + 8 {p}^{2} {q}^{2}  - 12 {q}^{4}  }{6} }

8.Rearrange terms.

 \sf{ \frac{8 {p}^{2}  {q}^{2}  - 12 {q}^{4}  + 9 {p}^{2} }{6} }

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