Math, asked by gayatrigayatridevi39, 2 months ago

Please please find the answer​

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Answered by aayushsharma7956
1

THE ANSWERS ARE GIVEN BELOW:-

1.

CP OF THE BIKE = ₹1,37,000

 LOSS% = 15%

 SO,

LET THE SP BE x

SO,

WE KNOW,

L% = (L/CP)*100

15 = [(137000-x)/137000]*100

(15/100)*137000 = (137000-x)

20550 = (137000-x)

x = 137000-20550

x = ₹116450

2.

 SP OF THE DOLL = ₹540

 P% = 20%

 SO,

 LET THE CP BE x

 SO,

 WE KNOW,

 P% = (P/CP)*100

 20 = [(540-x)/x]*100

 (20/100)x = (540-x)

 x/5 = (540-x)

 x = 5(540-x)

 x = 2700-5x

 x+5x = 2700

 6x = 2700

 x = ₹450

3.

 PARAMETERS GIVEN,

 PRINCIPAL = ₹5000

 RATE% = 11%

 TIME = 3 YEAR

 SO,

 SI = PRT/100

     = (5000*11*3)/100

     = ₹1650

SO,

AMOUNT = PRINCIPAL+INTEREST

                 = ₹5000+₹1650

                 = ₹6650

I HOPE YOU UNDERSTOOD THE QUESTION!!!

                          !!!JAI SHREE KRISHNA!!!

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