Math, asked by RamyasaSunjlina, 11 months ago

please please give me the correct answer

Attachments:

Atharv81: aisa nhi ho sakta kyuki mena hamesha badaa wala solve kiya ha..ya to mujhe nhi aata hoga sry
assthha161: which class question is this
Atharv81: ha to 10 ka hi
Atharv81: kyu aap sa nhi hua kua
Atharv81: kya
RamyasaSunjlina: actually it's of 9th
hele653: WHAT?
Atharv81: 9 ma kab sa trig. aati ha
hele653: ikr
Atharv81: full form

Answers

Answered by amitnrw
1

2Sinx + 3cosx = 3

2sinx = 3 - 3cosx

squaring both sides

4sin^2x = 9 + 9cos^2x - 18cosx

4 - 4cos^2x = 9 + 9cos^2x - 18cosx

13cos^2x - 18cos x + 5 = 0

13cos^2x -13cosx -5cosx + 5 = 0

13cosx(cosx -1) -5(cosx-1)= 0

(13cosx -5) (cosx -1) = 0

cosx = 5/13 or cosx = 1

if cos x = 1

2Sinx + 3cosx = 3

2sinx + 3 = 3

2sinx = 0

sinx = 0

tanx = sinx/cosx = 0

cosx = 5/13

2Sinx + 3cosx = 3

2sinx + 3(5/13) = 3

2sinx + 15/13 = 3

2sinx = 24/13

sinx = 12/13

tanx = sinx/cosx = 12/5

Answered by BrainlyPARCHO
0

  \green{  \fcolorbox{grey}{grey}{ \checkmark \:  \textsf{Verified \: answer}}}

Tan Q = 12/5

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