Question

please please give the answer fast and correct of both questions​

Answer 1

Answer:

1.(x-4)

2.4

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Answer 2

Answer:

Here is the answer =>

Step-by-step explanation:

1. Equation=>x^2+x-20.

Zero =>-5 (α)

Let other zero be ‘β’.

So α+β=-b/a

=> -5+β= -1/1

=>-5+β=-1

=>β=-1+5

=>β=4.

Now αβ=>c/a

-5(4)= -20/1

-20=-20

LHS=RHS.

Hence verified.

So x=4 is the verified other zero of polynomial x^2+x-20. So it's other factor is a) (x-4).

2. Equation=>x^3-2ax^2+16.

If (x+2) is a factor, then x=-2.

So p(-2)=0

=>x^3-2ax^2+16=0

=> (-2)^3-2(-2)^2(a)+16=0 (Putting x=-2).

=>-8-8a+16=0

=>-8a+8=0

=>-8a=-8

=>a=-8/-8

=>a=1.

So the value of a is b) 1 which is the required answer.

HOPE IT HELPS.