please please help me to do this question
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BE = BD = 30
CF = CD = 7
Let AF = x. Then, AE = x
From triangle ABC,
AB² + AC² = BC²
(x+30)² + (x+7)² = (30+7)²
x² + 37x - 210 = 0
(x+42)(x-5) = 0
Taking positive root, x = 5
So, AF = 5
Let O be the center of the circle. Then, OEAF will form a square.
Radius, OE or OF is same as AF
So, radius = 5
CF = CD = 7
Let AF = x. Then, AE = x
From triangle ABC,
AB² + AC² = BC²
(x+30)² + (x+7)² = (30+7)²
x² + 37x - 210 = 0
(x+42)(x-5) = 0
Taking positive root, x = 5
So, AF = 5
Let O be the center of the circle. Then, OEAF will form a square.
Radius, OE or OF is same as AF
So, radius = 5
Answered by
0
Answer:
af--5
so radios is 5........
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