Question

please please please​

Answer 1

Answer:

2) Option Li+ is correct

Answer 2

Answer:

2nd balmer transition 4 to 2

∆E=10.2eV is transition between 2 to 1 orbits of H

The same energy difference can be found in transition between 4 to 2 orbits of He+.

Explanation:

∆E= 13.6 z^2(1/n lower^2- 1/n higher^2)

from this formula

put ∆E=10.2

n lower =2

n higher =4

z comes out to be 2(approx) which signifies He+