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Answers
Answer:
12)In the given triangle, ∆ABC, AB, BC, and CA represent three sides. A, B and C are the three vertices and ∠ABC, ∠BCA and ∠CAB are three interior angles of ∆ABC.
Angle Sum Property of a Triangle
Theorem 1: Angle sum property of triangle states that the sum of interior angles of a triangle is 180°.
Proof:
Consider a ∆ABC, as shown in the figure below. To prove the above property of triangles, draw a line PQ←→ parallel to the side BC of the given triangle.
Since PQ is a straight line, it can be concluded that:
∠PAB + ∠BAC + ∠QAC = 180° ………(1)
SincePQ||BC and AB, AC are transversals,
Therefore, ∠QAC = ∠ACB (a pair of alternate angle)
Also, ∠PAB = ∠CBA (a pair of alternate angle)
Substituting the value of ∠QAC and∠PAB in equation (1),
∠ACB + ∠BAC + ∠CBA= 180°
Thus, the sum of the interior angles of a triangle is 180°
13)∠A=55,∠B=40,∠C=?
∠A+∠B+∠C=180
55+40+∠C=180
95+∠C=180
∠C=180-95=85
14)Let x stand for the measure of angle 1. Then. 2x for angle 2 and finally 3 x for angle 3.
So, x + 2x + 3x = 180
and 6x = 180
Therefore, x = 30, 2x = 60 and 3x = 90.
15)a)2+(3+4)=(2+3)+4
9=9=associative property
b)2*8=8*2
16=16=associative property.
16)5/6+11/13
=(65+66)/78
=131/78
=1.67
17)2/11*33/14
=66/154
=0.428
18)14 - 2 × 60 ÷ 15
=14-2*4
=14-8
=6
19)a)x+3=11
x=11-3=8
b)5x=3x+2
5x-3x=2
2x=2
x=1
Step-by step explanation
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