Question

please please please answwer only 2 hi to h​

Answer 1

Answer:

(i) In circle C(O, r)

AB is the diameter.

So ∠APB = 90˚ (Angle in semi–circle)

(ii) Now in △APB

∠PAB = 180˚ – (∠APB + ∠ABP)

= 180˚ – (90˚ + 42˚)

= 180˚ – 132˚ = 48˚

∠PQB = ∠PAB = 48˚ (Angles of the same segment )

Hence

∠PQB = 48˚

Answer 2

Answer:

✿$\large\mathbb{\underbrace\purple{ANSWER}}$

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