Question

Please please please anyone solve this
It's very very urgent​

Answer 1

Answer:

x=2 , y= -2/3

Step-by-step explanation:

$\sqrt[3]{(a^6)b^-4 }$=(a⁶b⁻⁴)$^{1/3}$

=$a^{6*(1/3)}b^{(-4)*(1/3)$

=$a^{2}b^{-4/3}$

=$a^{2}b^{2*(-2/3)}$

Comparing this with $a^{x}$$b^{2y}$, we get

x=2, y= -2/3

PLEASE RATE, THANK AND MARK AS BRAINLIEST.

Answer 2

Answer:

x=2 , y= -2/3

Step-by-step explanation:

\sqrt[3]{(a^6)b^-4 }

3

(a

6

)b

−

4

=(a⁶b⁻⁴)^{1/3}

1/3

=a^{6*(1/3)}b^{(-4)*(1/3)

=a^{2}b^{-4/3}a

2

b

−4/3

=a^{2}b^{2*(-2/3)}a

2

b

2∗(−2/3)

Comparing this with a^{x}a

x

b^{2y}b

2y

, we get

x=2, y= -2/3

PLEASE RATE, THANK AND MARK AS BRAINLIEST.