Question

please please please
give answer in steps​

Answer 1

Answer:

here,

AC = 9 cm and BC = 4 cm

then, by using Pythagoras theorem ,

AB +BC =AC

=> AB = BC - AC

= 4^2- 9^2

=16 - 81

= - 45

Answer 2

$\mathfrak{\huge{\underline{Answer:}}}$

$\texbf{\underline{\underline{Given\:In\:The\:Question:}}}$

Measurement of Base(BC) = 4 cm

Measurement of Hypotenuse(AC) = 9cm

$\textbf{\underline{\underline{According\: To\:Pythagoras'\:Theorem}}}$

Let's Find The Value Of Perpendicular

$\sf \: {h}^{2} = {p}^{2} + {b}^{2}$

$\sf \: {9}^{2} = {p}^{2} + {4}^{2}$

$\sf \: 81 = {p}^{2} + 16$

$\sf {p}^{2} = 81 - 16$

$\sf \: {p}^{2} = 65$

$\sf \: p = \sqrt{65}$

$\sf \: p = 8.02$

Now,Measure Of Base = 4cm

Hypotenuse = 9cm

And Perpendicular= 8.02 cm

Refer To The Attachment For Construction