Math, asked by anushka161, 1 year ago

please please please help me1st 2nd 3rd 4th 5th Sab karna hai unki sare parts karni hai

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Anonymous: we have to solve all parts??

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Answered by Anonymous
0
hiii!!!

here's ur answer...

2. \: (a) \: 4 \: and \: 4 \frac{2}{3} \\  \\ 4 \: and \:  \frac{14}{3}   \\  \\  =  \frac{4 \times 3}{1 \times 3}  =  \frac{12}{3}  \\  \\  =  \frac{12 \times 2}{3 \times 2}  =  \frac{24}{6}  \\  \\  =  \frac{14 \times 2}{3 \times 2}  =  \frac{28}{6}  \\  \\ three \: rational \: numbers \: between \: them \\ are \:  \frac{25}{6}  \:  \:  \frac{26}{6}  \: and \:  \frac{27}{6} . \\  \\ (b) \:  \frac{ - 1}{2}  \: and \:  - \frac{ - 1}{4}  \\  \\  =  \frac{ - 1 \times 2}{2 \times 2}  =   \frac{ - 2}{4}  \\  \\  =  \frac{ - 2 \times 4}{4 \times 4} =  \frac{ - 8}{16}   \\  \\  =  \frac{ - 1 \times 4}{4 \times 4}  =  \frac{ - 4}{16}  \\  \\ three \: rational \: numbers \: between \: them \\ are \:  \frac{ - 5}{16}  \:  \:  \frac{ - 6}{16}  \: and \:  \frac{ - 7}{16} . \\  \\ 2. \: (a) \:  \frac{3}{5}  \: and \:  \frac{2}{3}  \\  \\  =  \frac{3 \times 3}{5 \times 3}  =  \frac{9}{15}  \\  \\  =  \frac{2 \times 5}{3 \times 5}  =  \frac{10}{15 }  \\  \\  =  \frac{9 \times 6}{15 \times 6}  =  \frac{54}{90}  \\  \\  =  \frac{10 \times 6}{15 \times 6}  =  \frac{60}{90}  \\  \\ five \: rational \: numbers \: between \: them \\ are \:  \frac{55}{90}   \:  \:  \frac{56}{90}  \:  \:  \frac{57}{90}  \:  \:  \frac{58}{90}  \: and \:  \frac{59}{90}  \\  \\ (b) \:  - 2 \: and - 1 \frac{1}{2}  \\  \\  - 1 \frac{1}{2}  =  \frac{ - 3}{2}  \\  \\  =  \frac{ - 2 \times 2}{1 \times 2}  =  \frac{ - 4}{2}  \\  \\  =  \frac{ - 4 \times 6}{2 \times 6}  =  \frac{ - 24}{12}  \\  \\  =  \frac{ - 3 \times 6}{2 \times 6}  =  \frac{ - 18}{12}  \\  \\ five \: rational \: numbers \: between \: them \:  \\ are \:  \frac{ - 19}{12}  \:  \:  \frac{ - 20}{12}  \:  \:  \frac{ - 21}{12}  \:  \:  \frac{ - 22}{12}  \: and \:  \frac{ - 23}{12} . \\  \\ 4. \:  \frac{ - 3}{4}  \: and \:  \frac{5}{6}  \\  \\ lcm \: of \: 4 \: and \: 6 = 12 \\  \\  \frac{ - 3 \times 3}{4 \times 3}  =  \frac{ - 9}{12}  \\  \\  \frac{5  \times 2}{6 \times 2}  =  \frac{10}{12}  \\  \\ ten \: rational \: numbers \: between \: them \:  \\ are \:  \frac{ - 8}{12}  \:  \:  \frac{ - 7}{12}  \:  \:  \frac{ - 6}{12}  \:  \:  \frac{ - 5}{12}  \:  \:  \frac{ - 4}{12}  \:  \:  \frac{ - 3}{12}  \:  \:  \frac{ - 2}{12}  \:  \:  \frac{ - 1}{12}  \\  \frac{1}{12}  \: \:  \frac{2}{12}  \: etc. \\  \\ sorry \: i \: do \: not \: know \: to \: find \: rational \: \\  numbers \: between \: two \: numbers \: and \:  \\ are \: not \: fractions. \: so \: i \: have \: not \: solved \\ three \: question \: one \: is \: last \: one \: and \: other \:  \\ two \: are \: last \: part \: of \: 2nd \: and \: 3rd. \\  \\ sorry \: but \: it \: may \: help \: you...

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