Math, asked by sidharth93484, 11 months ago

PLEASE!!! PLEASE!!! PLEASE!!!


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Answered by jpg810
0

Answer:

 {5}^{x}  +  {5}^{x + 1}  +  {5}^{x + 2}  = 775

775 = 31 \times  {5}^{2}

 {5}^{x}  +  {5}^{x + 1}  + {5}^{x +  2}  = 31 \times  {5}^{2}

considering \:  \:  {5}^{x}  \: and \:  {5}^{2} \: as \:they \:are \:on\\ \:either\: side\: of\: equation

 {5}^{x}  =  {5}^{2}

x = 2

Now putting value of x in equation

 {5}^{2}  +  {5}^{2 + 1}  +  {5}^{2 + 2}  = 31 \times 25

25 + 125 + 625 = 775

775 = 775

Hence, value of x is 2

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