Math, asked by learner35, 10 months ago

Please please please please amswer my question. I am new to this app so i hope that you will not displeasure my expectations..... Answer both questions please​

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Answered by KnowMyPain
7

(1)

\displaystyle\text{Age of Dilip = x}\\\text{Age of Son = y}\\\\\\\textbf{\underline{Two years ago}}\\\\\text{Age of Dilip = x-2}\\\text{Age of Son = y-2}\\\\(x-2)=3(y-2)\\\\x-2=3y-6\\\\x=3y-4\:\:---[1]\\\\\\\textbf{\underline{Two years hence}}\\\\\text{Age of Dilip = x+2}\\\text{Age of Son = y+2}\\\\2(x+2)=5(y+2)\\\\2x+4=5y+10\\\\2x-5y=6\\\\\\\text{Substitute [1] for x}\\\\2(3y-4)-5y=6\\\\6y-8-5y=6\\\\\boxed{y=14}\\\\x=3y-4\\\\x=3(14)-4\\\\\boxed{x=42}

(2)

\text{Let the numerator = x}\\\text{Let the denominator = y}\\\\2x=y+2\\\\\implies y=2x-2\:\:---[1]\\\\\\\dfrac{(x+3)}{(y+3)}=\dfrac{2}{3}\\\\\\2(y+3)=3(x+3)\\\\\text{substitute [1] for y}\\\\2(2x-2+3)=3x+9\\\\2(2x+1)=3x+9\\\\(4x+2)=(3x+9)\\\\x=9-2\\\\\boxed{x=7}\\\\y=2x-2\\\\y=2(7)-2\\\\\boxed{y=12}\\\\\\\text{The fraction is}=\boxed{\boxed{\dfrac{7}{12}}}


learner35: thanks very much
KnowMyPain: no worries buddy : )
learner35: :)
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