Question

please please please please answer me​

Answer 1

Step-by-step explanation:

(1) In ∆ ABC altitude AD bisects BC.

(2) AD is perpendicular to BC.

To prove :- 

∆ ABC is an isosceles ∆.

Proof :-

In ∆ ABD and ∆ ACD :-

AD = AD (common)

BD = CD (AD bisects BC)

<ADB = <ADC (each are of 90° because AD is perpendicular to BC)

so,

∆ ABD ≈ ∆ ACD (SAS)

AB = AC (by CPCT)

now,

In ∆ ABC 

AB = AC

so, ∆ ABC is an isosceles ∆.

hope this helps you

### BE BRAINLY ###

Answer 2

Answer:

Step-by-step explanation:

(1) In ∆ ABC altitude AD bisects BC.

(2) AD is perpendicular to BC.

To prove :- 

∆ ABC is an isosceles ∆.

Proof :-

In ∆ ABD and ∆ ACD :-

AD = AD (common)

BD = CD (AD bisects BC)

<ADB = <ADC (each are of 90° because AD is perpendicular to BC)

so,

∆ ABD ≈ ∆ ACD (SAS)

AB = AC (by CPCT)

now,

In ∆ ABC 

AB = AC

so, ∆ ABC is an isosceles ∆.

hope this helps you