Question

please please please please answer this ​

Answer 1

Answer:

LET, √a+√b is rational

√a+√b=p/q

=>(√a+√b)² =(p/q)²

=>a+b+2√ab= (p/q)²

=>√ab= 1/2{(p/q)²-a-b}. .......[I]

now a and b are prime positive no. so √a and √b are irrational

also,

√ab

So, in equation 1 we get that

Rational =irrational

It is a contradiction

Hence, proved

Answer 2

Step-by-step explanation:

Answer:

LET, √a+√b is rational

√a+√b=p/q

=>(√a+√b)² =(p/q)²

=>a+b+2√ab= (p/q)²

=>√ab= 1/2{(p/q)²-a-b}. .......[I]

now a and b are prime positive no. so √a and √b are irrational

also,

√ab

So, in equation 1 we get that

Rational =irrational

It is a contradiction

Hence, proved