Physics, asked by rapideaf, 1 year ago

please please please please differentiate above question dy/dx

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Answered by abhi178
0
method 1 :-
y = t²

dy/dt = 2t -----(1)

x =2t³

dx/dt = 6t² -------------(1)

divide equation (1) and (2)

dy/dx = 2t/6t² = 1/3t

dy/dx = 1/3t


method 2 :-

y = t² and x= 2t³

put t = y½ in x= 2t³

x = 2(y½)³

x = 2y^3/2

differentiate wrt x

1 = 2×3/2 y½ dy/dx

1/3y½ = dy/dx

put y½ = t

dy/dx = 1/3t
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