please please please please differentiate above question dy/dx
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method 1 :-
y = t²
dy/dt = 2t -----(1)
x =2t³
dx/dt = 6t² -------------(1)
divide equation (1) and (2)
dy/dx = 2t/6t² = 1/3t
dy/dx = 1/3t
method 2 :-
y = t² and x= 2t³
put t = y½ in x= 2t³
x = 2(y½)³
x = 2y^3/2
differentiate wrt x
1 = 2×3/2 y½ dy/dx
1/3y½ = dy/dx
put y½ = t
dy/dx = 1/3t
y = t²
dy/dt = 2t -----(1)
x =2t³
dx/dt = 6t² -------------(1)
divide equation (1) and (2)
dy/dx = 2t/6t² = 1/3t
dy/dx = 1/3t
method 2 :-
y = t² and x= 2t³
put t = y½ in x= 2t³
x = 2(y½)³
x = 2y^3/2
differentiate wrt x
1 = 2×3/2 y½ dy/dx
1/3y½ = dy/dx
put y½ = t
dy/dx = 1/3t
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