Question

please please please please please please please please please please please please please please please please please please please please please answer answer answer​

Answer 1

Given: Angles are in ratio of 7:5

therefore 7x+5x = 180°

12x = 180°

x = 180/12

x = 60/4

x = 15

7x = 7*15 = 105°

5x = 5*15 = 75°

so Let all angles are A,B,C,D

A= C (opposite angle)

D= B (opposite angle)

Let A = 105° therefore , angle c = 105°

Let Angle B = 75° therefore angle c = 75°

$....$

Answer 2

Solution:

Let the two adjacent angles are 7x and 5x

Opposite angles of parallelogram are equal

So the four angles are 7x,5x,7x and 5x

Sum of the interior angles of parallelogram is 360°

7x + 5x + 7x + 5x = 360

24 x = 360

x = 360/24

x = 15

7x = 7 × 15 = 105°

5x = 5 × 15 = 75°

So, the four angles of parallelogram are

105°,75°,105° and 75° .