Question

Please please please please please please please please please please please please please please please please please answer this question... The question is — When a 22 ohms resistance is connected across its terminals a potential difference 2.2V is produced. Find the internal resistance and lost volt of the cell..Please solve ......​

Answer 1

Answer:

Explanation:

P.D.=2.2volts , this is the EMF of the cell.

Now when the circuit is closed and a current is flowing through the circuit then the P.D.=1.8V

Thus the total resistance of the circuit is R+r=5+rohms

So, the current in the circuit is i=(  5+r 2.2  )

hence the PD across the internal resistance.

Given that,

r(  5+r 2.2  )=2.2−1.8 as the drop in the potential across the battery is due the P.D. across the internal resistance.

So,

r(  5+r 2.2​   )=0.4  

1.8r=2

r=1.11ohms

i hope its help you

Answer 2

Answer:

P.D.=2.2volts , this is the EMF of the cell.

Now when the circuit is closed and a current is flowing through the circuit then the P.D.=1.8V

Thus the total resistance of the circuit is R+r=5+rohms

So, the current in the circuit is i=(

5+r

2.2

)

hence the PD across the internal resistance.

Given that,

r(

5+r

2.2

)=2.2−1.8 as the drop in the potential across the battery is due the P.D. across the internal resistance.

So,

r(

5+r

2.2

)=0.4

1.8r=2

r=1.11ohms