Question

please please please please please please please please answer the question​

Answer 1

x

3

+y

3

+z

3

−3xyz=(x+y+z)(x

2

+y

2

+z

2

−xy−yz−zx)

=(6){(x+y+z)

2

−2xy−2yz−2zx−xy−yz−zx}

=(6){(x+y+z)

2

−3xy−3yz−3zx}

=(6){(x+y+z)

2

−3(xy+yz+zx)}

=(6)(6

2

−3×12)

=(6)(36−36)

=0

Therefore,

x

3

+y

3

+z

3

=3xyz