Math, asked by stevesmith3, 1 year ago

please please please please please please please please please please please please please please please please solve this

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Answered by Anonymous
13

( \frac{ \sqrt{2} }{ \sqrt{3} } ) {}^{5} ( \frac{6}{7}  {)}^{2}  \\  \\ solve \: by \: using \: exponent \: rules \\  \\  \frac{ {2}^{2} \times  \sqrt{2}  }{ {3}^{2}  \times  \sqrt{ 3} }  \times \frac{36}{49}  \\  \\ evaluate \: the \: power \\  \\  \frac{4 \sqrt{2} }{9 \sqrt{3} }  \times  \frac{36}{49}  \\  \\ reduce \: 36 \: with \: 9 \\  \\  \frac{4 \sqrt{2} }{ \sqrt{3} }  \times  \frac{4}{49}  \\  \\ multiply


 \frac{4 \sqrt{2} \times 4 }{ \sqrt{3}  \times 49}  \\  \\  \frac{16 \sqrt{2} }{49 \sqrt{3} }  \\  \\ rationalize \: the \: denominator \\  \\  \frac{16 \sqrt{2} }{49 \sqrt{3} }  \times  \frac{ \sqrt{3} }{ \sqrt{3} }  \\  \\  \frac{16 \sqrt{2 \times 3} }{49( \sqrt{3}  {)}^{2} }  \\  \\  \frac{16 \sqrt{6} }{49 \times 3}  \\  \\  \frac{16 \sqrt{6} }{147}

=> 0.266 (approx.)

hariprasad2464p5dcjq: 0.265
Anonymous: amazing
Answered by Anonymous
0

Answer:

The answer is given in the image.

the answer is : 16√2÷49√3

Step-by-step explanation:

The sum that is given is the exponent sum. The sum that is given is root over two is divided by root over over three whole to the power five. It is multiplied by six divided seven whole to the power two.

the solution of this sum is given in the image. So kindly refer the image for further solution.



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