Question

please please please please please please please solve this question in notebook.

Answer 1

Answer:

$\boxed{\bold{\mathsf{Value = \frac{3}{2}}}}$

Step-by-step explanation:

Given :

f(x) = x² + x -2

Apply middle term splitting

x² + x -2 = 0

x² - x + 2x - 2 = 0

x(x - 1) + 2( x - 1) = 0

(x -1) ×(x+2) = 0

Equate the factors to zero to get the zeroes

(x -1) = 0

x = 1

$\rule{200}{1}$

(x+2) = 0

x = - 2

We get the two zeroes of this Quadratic polynomial as 1 , -2

Let $\bold{\mathsf{\alpha = 1 }}$

$\bold{\mathsf{\beta = -2 }}$

$\rule{200}{1}$

To find:

$\boxed{\bold{\mathsf{\frac{1}{\alpha} - \frac{1}{\beta} }}}$

Take L.C.M

$\huge{\bold{\mathsf{\frac{\beta - \alpha}{\alpha \beta} }}}$

Put in the values

$\frac{ - 2 - ( 1)}{ - 2} \\ \\ = \frac{ - 3}{ - 2} \\ \\ = \frac{3}{2}$

$\boxed{\bold{\mathsf{Value = \frac{3}{2}}}}$