Math, asked by yuvrajchoudhari865, 7 months ago

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Answers

Answered by tennetiraj86
21

Step-by-step explanation:

1)

a)7a-8

=>subtract 8 from 7 times 'a' (or)

Subtract 8 from the product of 7 and a

b)2b/5

=>two- fifth of 'b' (or) divide the product of 2 and b by 5

2)

Given numbers are 12,60,18

12= 2×2×3

60=2×2×3×5

18= 2×3×3

HCF of 12,60,18 = 2×3=6

HCF(12,60,18)=6

Answered by rani1201pushpa
1

Answer:

1)

a)7a-8

=>subtract 8 from 7 times 'a' (or)

Subtract 8 from the product of 7 and a

b)2b/5

=>two- fifth of 'b' (or) divide the product of 2 and b by 5

2)

Given numbers are 12,60,18

12= 2×2×3

60=2×2×3×5

18= 2×3×3

HCF of 12,60,18 = 2×3=6

HCF(12,60,18)=6

Step-by-step explanation:

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