Physics, asked by ankaja90, 9 months ago

please please please please solve it​

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Answers

Answered by SharmaShivam
2

Question:

\sf{Find\:\left(|\vec{a_1}-\vec{a_2|}\right)\left(2\vec{a_1}+\vec{a_2}\right)}

Solution:

\sf{|\vec{a_1}|=a_1=1}\\\sf{|\vec{a_2}|=a_2=1}

\sf{\left(|\vec{a_1}+\vec{a_2}|\right)^2=\left(\sqrt{3}\right)^2}

\sf{a_1^2+a_2^2+2\vec{a_1}.\vec{a_2}=3}

\sf{Now,a_1=a_2=1}

\sf{Therefore,\vec{a_1}.\vec{a_2}=\dfrac{1}{2}}

\sf{So,\left(\vec{a_1}-\vec{a_2}\right)\left(2\vec{a_1}+\vec{a_2}\right)}

\sf{2a_1^2+\vec{a_1}.\vec{a_2}-2\vec{a_1}.\vec{a_2}-a_2^2}

\sf{2-\dfrac{1}{2}-1}

\sf{1-\dfrac{1}{2}}

\boxed{\sf{\dfrac{1}{2}}}

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